What is the domain of f(x)= 1/(sqrt(2x-3)) ?

The domain of f(x)= 1/(sqrt(2x-3)) is x> 3/2

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domain of f(x)= 1/(sqrt(2x-3))

domain

f (x) = \frac{1}{2 x - 3}

x > \frac{3}{2}

Interval Notation

(\frac{3}{2}, \infty)

Solution steps

Find non-negative values for radicals:

x \geq \frac{3}{2}

Find undefined (singularity) points:

x = \frac{3}{2}

Combine real regions and undefined points for final function domain

x > \frac{3}{2}

6 y - 8 x = 54

35 L \times (- 8)

(3) (0.2)

f (x) = \frac{( 3 x - 5 )}{7}

sin (x - π)

What is the domain of f(x)= 1/(sqrt(2x-3)) ?
The domain of f(x)= 1/(sqrt(2x-3)) is x> 3/2