What is the inverse of f(x)=\sqrt[5]{2(x-8)+7} ?

The inverse of f(x)=\sqrt[5]{2(x-8)+7} is (x^5+9)/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=\sqrt[5]{2(x-8)+7}

inverse

\frac{x ^{5} + 9}{2}

Solution steps

Replace

x

with

y

Solve for

\frac{x ^{5} + 9}{2}

(x^{2} - 7)^{3}

f (x) = \frac{4}{3 + x}

y = (x + 2)^{2}

x^{3} - 6 x^{2} - 15 x + 3

f (x) = \frac{4}{x - 5}

What is the inverse of f(x)=\sqrt[5]{2(x-8)+7} ?
The inverse of f(x)=\sqrt[5]{2(x-8)+7} is (x^5+9)/2