What is the inverse of f(x)=3x^2-3 ?

The inverse of f(x)=3x^2-3 is sqrt((x+3)/3),-sqrt((x+3)/3)

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inverse of f(x)=3x^2-3

inverse

f (x) = 3 x^{2} - 3

\frac{x + 3}{3}, - \frac{x + 3}{3}

Solution steps

y = 3 x^{2} - 3

Replace

x

with

y

x = 3 y^{2} - 3

Solve for

y, x = 3 y^{2} - 3

\frac{x + 3}{3}, - \frac{x + 3}{3}

y = \frac{2 x - 1}{x + 3}

\frac{2 x - 16}{x ^{2} - 16 x}

sin (3 x)

cos (4 x)

\frac{2 x - 1}{3 x ^{2}}

What is the inverse of f(x)=3x^2-3 ?
The inverse of f(x)=3x^2-3 is sqrt((x+3)/3),-sqrt((x+3)/3)