What is the critical (x^2-1)/(x^3) ?

The critical (x^2-1)/(x^3) is x=-sqrt(3),x=sqrt(3)

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critical (x^2-1)/(x^3)

critical points

\frac{x ^{2} - 1}{x ^{3}}

x = - 3, x = 3

Solution steps

\frac{x ^{2} - 1}{x ^{3}}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 3, x = 3, x = 0

Identify critical points not in

f (x)

domain

Domain of

\frac{x ^{2} - 1}{x ^{3}} : x < 0 or x > 0

\frac{x ^{2} - 1}{x ^{3}}

is not defined at

x = 0

, therefore:

x = - 3, x = 3

f (x) = - \frac{2}{5} x^{6} + 5 x^{4}

f (x) = x 9 - x

f (x) = \frac{1}{x ^{2} - 1}

f (x) = 4 x + 4 - 5

(0, 2), (2, 0)

What is the critical (x^2-1)/(x^3) ?
The critical (x^2-1)/(x^3) is x=-sqrt(3),x=sqrt(3)