What is the range of sqrt(81-x^2) ?

The range of sqrt(81-x^2) is 0<= f(x)<= 9

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range of sqrt(81-x^2)

range

81 - x^{2}

0 \leq f (x) \leq 9

Interval Notation

[0, 9]

Solution steps

Find the minimum and maximum value in each defined interval and unite the results

Domain of

81 - x^{2} : - 9 \leq x \leq 9

Extreme Points of

81 - x^{2} :

Minimum

(- 9, 0),

Maximum

(0, 9),

Minimum

(9, 0)

Find the range for the interval

- 9 \leq x \leq 9 : 0 \leq f (x) \leq 9

Combine the ranges of all domain intervals to obtain the function range

0 \leq f (x) \leq 9

f (x) = 25 x^{3} - 3 x

f (x) = - 3 + 6 x - x^{3}

f (x) = 3 x^{2} + 1

125 x + 1200

y = sin (x - 4) - 1