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midpoint
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parallel 5x-3y=-6parallel domain of 1/(2sqrt(8-x))domain parity f(x)=x^2|x|+8parity inverse of f(x)=(18-x)^{1/4}inverse domain of f(x)= 1/3 sqrt(x)-4domain
Frequently Asked Questions (FAQ)
What is the midpoint (-3,5),(1,-9) ?
The midpoint (-3,5),(1,-9) is (-1,-2)