What is the extreme f(x)=-0.2t^2+1.6t+98.9 ?

The extreme f(x)=-0.2t^2+1.6t+98.9 is Maximum(4,102.1)

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extreme f(x)=-0.2t^2+1.6t+98.9

extreme points

f (x) = - 0.2 t^{2} + 1.6 t + 98.9

Maximum (4, 102.1)

Solution steps

f^{'} (t) = - 0.4 t + 1.6

Find intervals:

Increasing

: - \infty < t < 4,

Decreasing

: 4 < t < \infty

Plug

t = 4

into

- 0.2 t^{2} + 1.6 t + 98.9 : 102.1

Maximum (4, 102.1)

x + \frac{9}{x}

f (x) = \frac{5 + x}{5 + x}

f (x) = 9 + (5 x + 9)^{3}

f (x) = \frac{2 x ^{2} - 3}{x + 2}

What is the extreme f(x)=-0.2t^2+1.6t+98.9 ?
The extreme f(x)=-0.2t^2+1.6t+98.9 is Maximum(4,102.1)