What is the domain of f(x)=(2x+3)sqrt(x^2+8) ?

The domain of f(x)=(2x+3)sqrt(x^2+8) is -infinity <x<infinity

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domain of f(x)=(2x+3)sqrt(x^2+8)

domain

f (x) = (2 x + 3) x^{2} + 8

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

Find non-negative values for radicals:

- \infty < x < \infty

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

\frac{x + 9}{2}

f (x) = x^{2} + 25

f (x) = 3 x^{2} - x^{3}

f (x) = 3 x + 2 - lo g_{e} (x^{2} - 1)

f (x) = \frac{5 x + 7 x ^{4}}{4 - x ^{2}}

What is the domain of f(x)=(2x+3)sqrt(x^2+8) ?
The domain of f(x)=(2x+3)sqrt(x^2+8) is -infinity <x<infinity