What is the line (1992,61.6),(1997,64) ?

The line (1992,61.6),(1997,64) is y=0.48x-894.56

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line (1992,61.6),(1997,64)

line

(1992, 61.6), (1997, 64)

y = 0.48 x - 894.56

Solution steps

Find the line

y = mx + b

passing through

(1992, 61.6)

(1997, 64)

Compute the slope

(1992, 61.6), (1997, 64) : m = 0.48

Compute the

y

intercept:

b = - 894.56

Construct the line equation

y = mx + b

where

m = 0.48

and

b = - 894.56

y = 0.48 x - 894.56

- 3 x + 2 y = 6

(- 6, 6), (- 3, 3)

f (x) = \frac{4 - 3 x}{x - 7}

\frac{1}{x ^{2} + 2 x}

f (x) = 3 x (x - 2)

What is the line (1992,61.6),(1997,64) ?
The line (1992,61.6),(1997,64) is y=0.48x-894.56