What is the domain of f(x)=sqrt(64-t^2) ?

The domain of f(x)=sqrt(64-t^2) is -8<= t<= 8

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domain of f(x)=sqrt(64-t^2)

domain

f (x) = 64 - t^{2}

- 8 \leq t \leq 8

Interval Notation

[- 8, 8]

Solution steps

Find non-negative values for radicals:

- 8 \leq t \leq 8

The function domain

- 8 \leq t \leq 8

f (x) = 9 x + 1

f (x) = \frac{x - 4}{x ^{2} + 1}

f (x) = 3

f (x) = - \frac{8}{3} x - \frac{43}{3}

(3, 7), (2, 3)

What is the domain of f(x)=sqrt(64-t^2) ?
The domain of f(x)=sqrt(64-t^2) is -8<= t<= 8