What is the domain of f(x)=sqrt(3-2x) ?

The domain of f(x)=sqrt(3-2x) is x<= 3/2

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domain of f(x)=sqrt(3-2x)

domain

f (x) = 3 - 2 x

x \leq \frac{3}{2}

Interval Notation

(- \infty, \frac{3}{2}]

Solution steps

Find non-negative values for radicals:

x \leq \frac{3}{2}

The function domain

x \leq \frac{3}{2}

y = (x + 4)^{2}

y - 6 = 0, (- 2, 5)

\frac{x ^{2}}{x + 1}

f (x) = y - 14

f (x) = \frac{x ^{2} - 7 x + 12}{x ^{2} - 9}

What is the domain of f(x)=sqrt(3-2x) ?
The domain of f(x)=sqrt(3-2x) is x<= 3/2