What is the domain of f(x)= 1/(t^2-4) ?

The domain of f(x)= 1/(t^2-4) is t 2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)= 1/(t^2-4)

domain

f (x) = \frac{1}{t ^{2} - 4}

t < - 2 or - 2 < t < 2 or t > 2

Interval Notation

(- \infty, - 2) \cup (- 2, 2) \cup (2, \infty)

Solution steps

Find undefined (singularity) points:

t = 2, t = - 2

The function domain

t < - 2 or - 2 < t < 2 or t > 2

x e^{\frac{1}{x}}

f (x) = \frac{sin ( x )}{x ^{2} + 1}

f (x) = \frac{e ^{x} ( 1 - x )}{9 x ^{2}}

f (x) = \frac{1}{1 - \frac{1}{x - 2}}

x^{2} - 2 x - 3

What is the domain of f(x)= 1/(t^2-4) ?
The domain of f(x)= 1/(t^2-4) is t<-2\lor-2<t<2\lor t>2