What is the inverse of f(x)=-(x-3)^2+1 ?

The inverse of f(x)=-(x-3)^2+1 is sqrt(-x+1)+3,-sqrt(-x+1)+3

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inverse of f(x)=-(x-3)^2+1

inverse

f (x) = - (x - 3)^{2} + 1

- x + 1 + 3, - - x + 1 + 3

Solution steps

y = - (x - 3)^{2} + 1

Replace

x

with

y

x = - (y - 3)^{2} + 1

Solve for

y, x = - (y - 3)^{2} + 1

- x + 1 + 3, - - x + 1 + 3

(1, 1), (4, - 1)

f (x) = - 5 x + 6

f (x) = 2 x - 5

h (x) = \frac{4 - x ^{2}}{x ^{2} - x - 6}

f (x) = ∣ x ∣ + x

What is the inverse of f(x)=-(x-3)^2+1 ?
The inverse of f(x)=-(x-3)^2+1 is sqrt(-x+1)+3,-sqrt(-x+1)+3