What is the domain of f(x)=sqrt(2x-48) ?

The domain of f(x)=sqrt(2x-48) is x>= 24

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domain of f(x)=sqrt(2x-48)

domain

f (x) = 2 x - 48

x \geq 24

Interval Notation

[24, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 24

The function domain

x \geq 24

(- 3) (- 11.9)

f (x) = x^{3} - 5 x^{2} - 8 x - 4

f (x) = \frac{2}{4 - 3 x + x ^{2}}

f (x) = x^{2} - 4 x + 2

f (x) = (x + 4)^{2}

What is the domain of f(x)=sqrt(2x-48) ?
The domain of f(x)=sqrt(2x-48) is x>= 24