What is the inverse of f(x)=((1-2x))/(1-3x) ?

The inverse of f(x)=((1-2x))/(1-3x) is (1-x)/(-3x+2)

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inverse of f(x)=((1-2x))/(1-3x)

inverse

f (x) = \frac{( 1 - 2 x )}{1 - 3 x}

\frac{1 - x}{- 3 x + 2}

Solution steps

y = \frac{1 - 2 x}{1 - 3 x}

Replace

x

with

y

x = \frac{1 - 2 y}{1 - 3 y}

Solve for

y, x = \frac{1 - 2 y}{1 - 3 y}

\frac{1 - x}{- 3 x + 2}

f (x) = 4 x + 6 y - 15 = 0

f (x) = \frac{2}{3 x + 7}

f (x) = 3 x - 8

\frac{5 ( x + 7 )}{7 x}

f (x) = 4 x

What is the inverse of f(x)=((1-2x))/(1-3x) ?
The inverse of f(x)=((1-2x))/(1-3x) is (1-x)/(-3x+2)