What is the domain of f(x)= 1/(x^2-16) ?

The domain of f(x)= 1/(x^2-16) is x 4

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domain of f(x)= 1/(x^2-16)

domain

f (x) = \frac{1}{x ^{2} - 16}

x < - 4 or - 4 < x < 4 or x > 4

Interval Notation

(- \infty, - 4) \cup (- 4, 4) \cup (4, \infty)

Solution steps

Find undefined (singularity) points:

x = 4, x = - 4

The function domain

x < - 4 or - 4 < x < 4 or x > 4

f (x) = (3 x - 24)^{4}

- x + 2

f (x) = ln (\frac{x}{x - 2})

f (x) = \frac{1}{4} x + 5

f (x) = \frac{( x + 5 )}{x ^{2} - 25}

What is the domain of f(x)= 1/(x^2-16) ?
The domain of f(x)= 1/(x^2-16) is x<-4\lor-4<x<4\lor x>4