What is the inverse of f(x)=(3x-4)^2 ?

The inverse of f(x)=(3x-4)^2 is (sqrt(x)+4)/3 ,(-sqrt(x)+4)/3

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inverse of f(x)=(3x-4)^2

inverse

f (x) = (3 x - 4)^{2}

\frac{x + 4}{3}, \frac{- x + 4}{3}

Solution steps

y = (3 x - 4)^{2}

Replace

x

with

y

x = (3 y - 4)^{2}

Solve for

y, x = (3 y - 4)^{2}

\frac{x + 4}{3}, \frac{- x + 4}{3}

x cos (x) + 2 tan (x)

f (x) = 2 x - 3

y = x^{2} + 2 x

- \frac{3}{2}

x - 3 y = - 6

What is the inverse of f(x)=(3x-4)^2 ?
The inverse of f(x)=(3x-4)^2 is (sqrt(x)+4)/3 ,(-sqrt(x)+4)/3