What is the inverse of f(x)=((4x-1))/(2x+3) ?

The inverse of f(x)=((4x-1))/(2x+3) is (-1-3x)/(2(-2+x))

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inverse of f(x)=((4x-1))/(2x+3)

inverse

f (x) = \frac{( 4 x - 1 )}{2 x + 3}

\frac{- 1 - 3 x}{2 ( - 2 + x )}

Solution steps

y = \frac{4 x - 1}{2 x + 3}

Replace

x

with

y

x = \frac{4 y - 1}{2 y + 3}

Solve for

y, x = \frac{4 y - 1}{2 y + 3}

\frac{- 1 - 3 x}{2 ( - 2 + x )}

f (x) = \frac{1 - 3 t}{5 + t}

y = 64 - x^{3}

f (x) = \frac{x ^{3}}{x + 1}

f (x) = x^{4} - 8 x^{2}

(x - 1)^{2} + 1

What is the inverse of f(x)=((4x-1))/(2x+3) ?
The inverse of f(x)=((4x-1))/(2x+3) is (-1-3x)/(2(-2+x))