What is the inverse of f(x)=sqrt(2x-1)-3 ?

The inverse of f(x)=sqrt(2x-1)-3 is (x^2+6x+10)/2

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inverse of f(x)=sqrt(2x-1)-3

inverse

f (x) = 2 x - 1 - 3

\frac{x ^{2} + 6 x + 10}{2}

Solution steps

y = 2 x - 1 - 3

Replace

x

with

y

x = 2 y - 1 - 3

Solve for

y, x = 2 y - 1 - 3

\frac{x ^{2} + 6 x + 10}{2}

g (x) = \frac{1}{x ^{2} + 8}

234

f (x) = x^{3} - 27 x, - 4 \leq x \leq 4

y = 4.5

tan^{2} (x)

What is the inverse of f(x)=sqrt(2x-1)-3 ?
The inverse of f(x)=sqrt(2x-1)-3 is (x^2+6x+10)/2