What is the critical-4cos(3x+pi/6)+1 ?

The critical-4cos(3x+pi/6)+1 is x=(5pi}{18}+(2pi)/3 n,x=(11pi)/(18)+\frac{2pi)/3 n

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critical-4cos(3x+pi/6)+1

critical points

- 4 cos (3 x + \frac{π}{6}) + 1

x = \frac{5 π}{18} + \frac{2 π}{3} n, x = \frac{11 π}{18} + \frac{2 π}{3} n

Solution steps

- 4 cos (3 x + \frac{π}{6}) + 1

Find where

f^{'} (x)

is equal to zero or undefined

x = \frac{5 π}{18} + \frac{2 π}{3} n, x = \frac{11 π}{18} + \frac{2 π}{3} n

Identify critical points not in

f (x)

domain

Domain of

- 4 cos (3 x + \frac{π}{6}) + 1 : - \infty < x < \infty

All critical points are in domain

x = \frac{5 π}{18} + \frac{2 π}{3} n, x = \frac{11 π}{18} + \frac{2 π}{3} n

\frac{- 2}{x ^{2} - 5 x + 6}

2 x^{2} + x - 6

f (x) = - (x + 1) (x - 1)^{2}

f (x) = 2 x - x^{2} + 1

What is the critical-4cos(3x+pi/6)+1 ?
The critical-4cos(3x+pi/6)+1 is x=(5pi}{18}+(2pi)/3 n,x=(11pi)/(18)+\frac{2pi)/3 n