What is the midpoint ((2pi)/6 ,0),((7pi)/(12),0) ?

The midpoint ((2pi)/6 ,0),((7pi)/(12),0) is ((11pi)/(24),0)

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midpoint ((2pi)/6 ,0),((7pi)/(12),0)

midpoint

(\frac{2 π}{6}, 0), (\frac{7 π}{12}, 0)

(\frac{11 π}{24}, 0)

Solution steps

Midpoint of

(x_{1}, y_{1}), (x_{2}, y_{2})

(\frac{x _{2} + x _{1}}{2}, \frac{y _{2} + y _{1}}{2})

(x_{1}, y_{1}) = (\frac{2 π}{6}, 0), (x_{2}, y_{2}) = (\frac{7 π}{12}, 0)

= (\frac{\frac{7 π}{12} + \frac{2 π}{6}}{2}, \frac{0 + 0}{2})

Refine

= (\frac{11 π}{24}, 0)

f (x) = - x^{3} - 48 x

f (x) = \frac{3 x ^{2} + 1}{x + 1}

f (x) = (\frac{2}{3})^{x}

f (x) = \frac{x}{x + 8}

f (x) = 1 + x - 1 - x

What is the midpoint ((2pi)/6 ,0),((7pi)/(12),0) ?
The midpoint ((2pi)/6 ,0),((7pi)/(12),0) is ((11pi)/(24),0)