What is the domain of f(x)=(sqrt(5+x))/(9-x) ?

The domain of f(x)=(sqrt(5+x))/(9-x) is -5 9

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domain of f(x)=(sqrt(5+x))/(9-x)

domain

f (x) = \frac{5 + x}{9 - x}

- 5 \leq x < 9 or x > 9

Interval Notation

[- 5, 9) \cup (9, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 5

Find undefined (singularity) points:

x = 9

Combine real regions and undefined points for final function domain

- 5 \leq x < 9 or x > 9

f (x) = (\frac{- x ^{4}}{4}) + x^{2} - 1

(4, 5), (3, 2)

f (x) = \frac{5 x}{x - 2}

f (x) = \frac{x + 3}{3 - x}

f (x) = 2 x^{2} + 4 x + 3

What is the domain of f(x)=(sqrt(5+x))/(9-x) ?
The domain of f(x)=(sqrt(5+x))/(9-x) is -5<= x<9\lor x>9