What is the inverse of f(x)=9x^2-4 ?

The inverse of f(x)=9x^2-4 is (sqrt(x+4))/3 ,-(sqrt(x+4))/3

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inverse of f(x)=9x^2-4

inverse

f (x) = 9 x^{2} - 4

\frac{x + 4}{3}, - \frac{x + 4}{3}

Solution steps

y = 9 x^{2} - 4

Replace

x

with

y

x = 9 y^{2} - 4

Solve for

y, x = 9 y^{2} - 4

\frac{x + 4}{3}, - \frac{x + 4}{3}

x^{2} + \frac{1}{x} - 1

3 - x + 1

f (x) = 9 x^{7} + 7

f (x) = 1 + x^{3}

f (x) = \frac{( 3 x + 2 )}{2 x - 1}

What is the inverse of f(x)=9x^2-4 ?
The inverse of f(x)=9x^2-4 is (sqrt(x+4))/3 ,-(sqrt(x+4))/3