What is the inverse of f(x)=\sqrt[3]{x}+2 ?

The inverse of f(x)=\sqrt[3]{x}+2 is x^3-6x^2+12x-8

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inverse of f(x)=\sqrt[3]{x}+2

inverse

x^{3} - 6 x^{2} + 12 x - 8

Solution steps

Replace

x

with

y

Solve for

x^{3} - 6 x^{2} + 12 x - 8

f (θ) = cos (2 θ)

f (x) = \frac{6 - 5 x}{3 x - 7}

f (x) = - \frac{x}{4}

f (x) = \frac{8}{\frac{6}{x} - 1}

f (x) = 5 x^{2} - 10 x

What is the inverse of f(x)=\sqrt[3]{x}+2 ?
The inverse of f(x)=\sqrt[3]{x}+2 is x^3-6x^2+12x-8