What is the critical f(x)= 1/2 x^2+4x+1 ?

The critical f(x)= 1/2 x^2+4x+1 is x=-4

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critical f(x)= 1/2 x^2+4x+1

critical points

f (x) = \frac{1}{2} x^{2} + 4 x + 1

x = - 4

Solution steps

\frac{1}{2} x^{2} + 4 x + 1

Find where

f^{'} (x)

is equal to zero or undefined

x = - 4

Identify critical points not in

f (x)

domain

Domain of

\frac{1}{2} x^{2} + 4 x + 1 : - \infty < x < \infty

All critical points are in domain

x = - 4

y = \frac{e ^{x}}{1 + 5 e ^{x}}

2 sin (\frac{x - π}{3})

f (x) = \frac{2}{x ^{2} + 4}

y = 2 sin (6 x - π)

e^{- x} - 5

What is the critical f(x)= 1/2 x^2+4x+1 ?
The critical f(x)= 1/2 x^2+4x+1 is x=-4