What is the perpendicular y=3x+1,(-3,6) ?

The perpendicular y=3x+1,(-3,6) is y=-1/3 x+5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

perpendicular y=3x+1,(-3,6)

perpendicular

y = 3 x + 1, (- 3, 6)

y = - \frac{1}{3} x + 5

Solution steps

Find the line

y = mx + b

perpendicular to

y = 3 x + 1

that passes through

(- 3, 6)

Find the slope of

y = 3 x + 1 : m = 3

Compute the slope of the perpendicular line:

m_{p} = - \frac{1}{3}

Find the line with slope m=

- \frac{1}{3}

and passing through

(- 3, 6) : y = - \frac{1}{3} x + 5

y = - \frac{1}{3} x + 5

f (x) = \frac{- 5 x - 15}{2 x ^{2} + 5 x - 3}

f (x) = \frac{3}{2} x - 6

f (x) = \frac{6}{x - 9}

2 x - 5 y = 0

f (x) = 2 x^{4}

What is the perpendicular y=3x+1,(-3,6) ?
The perpendicular y=3x+1,(-3,6) is y=-1/3 x+5