What is the critical x^2ln(x/8) ?

The critical x^2ln(x/8) is x= 8/(sqrt(e))

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critical x^2ln(x/8)

critical points

x^{2} ln (\frac{x}{8})

x = \frac{8}{e}

Solution steps

x^{2} ln (\frac{x}{8})

Find where

f^{'} (x)

is equal to zero or undefined

x = \frac{8}{e}, x = 0

Identify critical points not in

f (x)

domain

Domain of

x^{2} ln (\frac{x}{8}) : x > 0

x^{2} ln (\frac{x}{8})

is not defined at

x = 0

, therefore:

x = \frac{8}{e}

x - 4 y = - 28

\frac{2 x ^{2} - 4 x}{x ^{2} + 4 x + 4}

f (x) = x^{4} - 8 x^{3} + 10 x^{2}

f (x) = 6 x + 7

(- 3, 7), (3, 3)