What is the perpendicular y=-7x+3,(-4,5) ?

The perpendicular y=-7x+3,(-4,5) is y= 1/7 x+39/7

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perpendicular y=-7x+3,(-4,5)

perpendicular

y = - 7 x + 3, (- 4, 5)

y = \frac{1}{7} x + \frac{39}{7}

Solution steps

Find the line

y = mx + b

perpendicular to

y = - 7 x + 3

that passes through

(- 4, 5)

Find the slope of

y = - 7 x + 3 : m = - 7

Compute the slope of the perpendicular line:

m_{p} = \frac{1}{7}

Find the line with slope m=

\frac{1}{7}

and passing through

(- 4, 5) : y = \frac{1}{7} x + \frac{39}{7}

y = \frac{1}{7} x + \frac{39}{7}

9 - x

f (x) = \frac{x + 1}{x - 5}

y = 5 x - 6

y = - \frac{1}{3} x - 6, (- 1, 5)

lo g_{2} (x)

What is the perpendicular y=-7x+3,(-4,5) ?
The perpendicular y=-7x+3,(-4,5) is y= 1/7 x+39/7