What is the domain of (sqrt(x-4))^2-5 ?

The domain of (sqrt(x-4))^2-5 is x>= 4

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domain of (sqrt(x-4))^2-5

domain

(x - 4)^{2} - 5

x \geq 4

Interval Notation

[4, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 4

The function domain

x \geq 4

tan (4 x)

(- 2) (8.2)

f (x) = 1.5 x^{2} - 4

f (x) = \frac{( x - 3 )}{x ^{2}}

f (x) = \frac{5 x ^{2} + x - 9}{x ^{2} + 1}