What is the inverse of f(x)=x^2-3x-4 ?

The inverse of f(x)=x^2-3x-4 is (3+sqrt(4x+25))/2 ,(3-sqrt(4x+25))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=x^2-3x-4

inverse

f (x) = x^{2} - 3 x - 4

\frac{3 + 4 x + 25}{2}, \frac{3 - 4 x + 25}{2}

Solution steps

y = x^{2} - 3 x - 4

Replace

x

with

y

x = y^{2} - 3 y - 4

Solve for

y, x = y^{2} - 3 y - 4

\frac{3 + 4 x + 25}{2}, \frac{3 - 4 x + 25}{2}

\frac{x ^{2} - 1}{x}

y = 4 x + c

f (x) = \frac{9 x ^{2} + 12 x}{9 x + 12}

(5.8) (- 1.6)

f (x) = - x^{2} + 4 x

What is the inverse of f(x)=x^2-3x-4 ?
The inverse of f(x)=x^2-3x-4 is (3+sqrt(4x+25))/2 ,(3-sqrt(4x+25))/2