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Popular >

distance (8,10),(-2,14)

Solution

distance

(8, 10), (- 2, 14)

Solution

229

Solution steps

The distance between

(x_{1}, y_{1}), (x_{2}, y_{2})

is:

(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}

The distance between

(8, 10)

and

(- 2, 14)

is

= (- 2 - 8)^{2} + (14 - 10)^{2}

Simplify

= 229

Popular Examples

inverse of f(x)=x^2-2x inverse

f (x) = x^{2} - 2 x

asymptotes of x asymptotes

x

domain of (2x)/(x^2+81)domain

\frac{2 x}{x ^{2} + 81}

parallel y=2x+7(-1.1)parallel

y = 2 x + 7 (- 1.1)

range of (6x+7)/(x+6)range

\frac{6 x + 7}{x + 6}

Frequently Asked Questions (FAQ)

What is the distance (8,10),(-2,14) ?
The distance (8,10),(-2,14) is 2sqrt(29)