What is the asymptotes of f(x)=((x^2+2))/(5x-2x^2) ?

The asymptotes of f(x)=((x^2+2))/(5x-2x^2) is Vertical: x=0,x= 5/2 ,Horizontal: y=-1/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

asymptotes of f(x)=((x^2+2))/(5x-2x^2)

asymptotes

f (x) = \frac{( x ^{2} + 2 )}{5 x - 2 x ^{2}}

Vertical : x = 0, x = \frac{5}{2}, Horizontal : y = - \frac{1}{2}

Solution steps

Vertical asymptotes of

\frac{x ^{2} + 2}{5 x - 2 x ^{2}} : x = 0, x = \frac{5}{2}

Horizontal Asymptotes of

\frac{x ^{2} + 2}{5 x - 2 x ^{2}} : y = - \frac{1}{2}

Slant Asymptotes of

\frac{x ^{2} + 2}{5 x - 2 x ^{2}} :

None

Vertical : x = 0, x = \frac{5}{2}, Horizontal : y = - \frac{1}{2}

f (x) = \frac{x ^{2} - 5 x - 1}{x - 3}

f (x) = \frac{x + 1}{x + 6}

f (x) = \frac{3}{x - 1} + 4

f (x) = 8 + \frac{64}{x}

What is the asymptotes of f(x)=((x^2+2))/(5x-2x^2) ?
The asymptotes of f(x)=((x^2+2))/(5x-2x^2) is Vertical: x=0,x= 5/2 ,Horizontal: y=-1/2