What is the inverse of y=log_{7}(2x-5)+9 ?

The inverse of y=log_{7}(2x-5)+9 is (7^{x-9}+5)/2

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inverse of y=log_{7}(2x-5)+9

inverse

y = lo g_{7} (2 x - 5) + 9

\frac{7 ^{x - 9} + 5}{2}

Solution steps

y = lo g_{7} (2 x - 5) + 9

Replace

x

with

y

x = lo g_{7} (2 y - 5) + 9

Solve for

y, x = lo g_{7} (2 y - 5) + 9

\frac{7 ^{x - 9} + 5}{2}

\frac{- 3 x - 3}{x - 1}

f (x) = \frac{x}{- 8 x + 3}

F (t) = \frac{t}{∣ t ∣}

(0, 0), (2, 2)

\frac{- 5 x}{4 x + 10}

What is the inverse of y=log_{7}(2x-5)+9 ?
The inverse of y=log_{7}(2x-5)+9 is (7^{x-9}+5)/2