What is the inverse of f(x)=(x^7-2)^9 ?

The inverse of f(x)=(x^7-2)^9 is \sqrt[7]{\sqrt[9]{x}+2}

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inverse of f(x)=(x^7-2)^9

inverse

f (x) = (x^{7} - 2)^{9}

Solution steps

y = (x^{7} - 2)^{9}

Replace

x

with

y

x = (y^{7} - 2)^{9}

Solve for

y, x = (y^{7} - 2)^{9}

f (x) = lo g_{2} (x + 2)

(x - 5)^{2} - 9

e^{- 0.5 x^{2}}

\frac{4 x + 16}{x}

f (x) = \frac{x}{1 - x ^{2}}

What is the inverse of f(x)=(x^7-2)^9 ?
The inverse of f(x)=(x^7-2)^9 is \sqrt[7]{\sqrt[9]{x}+2}