What is the domain of (sqrt(x-2))/(x-10) ?

The domain of (sqrt(x-2))/(x-10) is 2 10

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domain of (sqrt(x-2))/(x-10)

domain

\frac{x - 2}{x - 10}

2 \leq x < 10 or x > 10

Interval Notation

[2, 10) \cup (10, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 2

Find undefined (singularity) points:

x = 10

Combine real regions and undefined points for final function domain

2 \leq x < 10 or x > 10

f (x) = \frac{3 x - 15}{- x ^{2} + 5 x}

h (x) = 4^{x} - 2

(9, 9), (8, 6)

5 - x + 13

9 x^{2} + y^{2} = 9

What is the domain of (sqrt(x-2))/(x-10) ?
The domain of (sqrt(x-2))/(x-10) is 2<= x<10\lor x>10