What is the domain of f(x)=sqrt(1/(x-2)) ?

The domain of f(x)=sqrt(1/(x-2)) is x>2

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domain of f(x)=sqrt(1/(x-2))

domain

f (x) = \frac{1}{x - 2}

x > 2

Interval Notation

(2, \infty)

Solution steps

Find non-negative values for radicals:

x > 2

Find undefined (singularity) points:

x = 2

Combine real regions and undefined points for final function domain

x > 2

- 1 = - 2 x + y

y = 8 + t

f (x) = x^{\frac{1}{3}}

f (x) = x - 2

- 3 x + 2

What is the domain of f(x)=sqrt(1/(x-2)) ?
The domain of f(x)=sqrt(1/(x-2)) is x>2