What is the inverse of f(x)=sqrt(16-x^2) ?

The inverse of f(x)=sqrt(16-x^2) is sqrt(-x^2+16),-sqrt(-x^2+16)

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inverse of f(x)=sqrt(16-x^2)

inverse

f (x) = 16 - x^{2}

- x^{2} + 16, - - x^{2} + 16

Solution steps

y = 16 - x^{2}

Replace

x

with

y

x = 16 - y^{2}

Solve for

y, x = 16 - y^{2}

- x^{2} + 16, - - x^{2} + 16

5 y - 7 x = 11

(6.4) (10.1)

\frac{x ^{2} - 9 x + 39}{x - 7}

x^{2} - 6 x - 3

f (x) = 4 x - 6 y = 36

What is the inverse of f(x)=sqrt(16-x^2) ?
The inverse of f(x)=sqrt(16-x^2) is sqrt(-x^2+16),-sqrt(-x^2+16)