What is the extreme f(x)=x^4e^x-7 ?

The extreme f(x)=x^4e^x-7 is Maximum(-4,(256)/(e^4)-7),Minimum(0,-7)

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extreme f(x)=x^4e^x-7

extreme points

f (x) = x^{4} e^{x} - 7

Maximum (- 4, \frac{256}{e ^{4}} - 7), Minimum (0, - 7)

Solution steps

f^{'} (x) = e^{x} x^{4} + 4 e^{x} x^{3}

Find intervals:

Increasing

: - \infty < x < - 4,

Decreasing

: - 4 < x < 0,

Increasing

: 0 < x < \infty

Plug

x = - 4

into

x^{4} e^{x} - 7 : \frac{256}{e ^{4}} - 7

Maximum (- 4, \frac{256}{e ^{4}} - 7)

Plug

x = 0

into

x^{4} e^{x} - 7 : - 7

Minimum (0, - 7)

Maximum (- 4, \frac{256}{e ^{4}} - 7), Minimum (0, - 7)

x - 2 y = - 20

f (x) = sin (2 x) + cos (x)

y = x^{2} + 6 x + 8

\frac{1}{x ^{2} + 3}

16 - x^{2} \cdot x + 3

What is the extreme f(x)=x^4e^x-7 ?
The extreme f(x)=x^4e^x-7 is Maximum(-4,(256)/(e^4)-7),Minimum(0,-7)