What is the domain of f(x)=sqrt(3+8x) ?

The domain of f(x)=sqrt(3+8x) is x>=-3/8

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=sqrt(3+8x)

domain

f (x) = 3 + 8 x

x \geq - \frac{3}{8}

Interval Notation

[- \frac{3}{8}, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - \frac{3}{8}

The function domain

x \geq - \frac{3}{8}

\frac{3}{x + 4} - ln (x^{2} - x - 6)

(- 3, - 3), (2, 9)

(5.5) (- 3.3)

f (2) = 2 x + 1

(8.2) (18.4)

What is the domain of f(x)=sqrt(3+8x) ?
The domain of f(x)=sqrt(3+8x) is x>=-3/8