What is the domain of f(x)=(\sqrt[3]{4x+9})/(12x+5) ?

The domain of f(x)=(\sqrt[3]{4x+9})/(12x+5) is x -5/12

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domain of f(x)=(\sqrt[3]{4x+9})/(12x+5)

domain

x < - \frac{5}{12} or x > - \frac{5}{12}

Interval Notation

(- \infty, - \frac{5}{12}) \cup (- \frac{5}{12}, \infty)

Solution steps

Find undefined (singularity) points:

x = - \frac{5}{12}

The function domain

x < - \frac{5}{12} or x > - \frac{5}{12}

f (x) = x^{4} - 4 x^{3} + 6

ln (x + 1)

f (x) = - 4 x^{2} + 12

f (x) = ln (5 x)

\frac{cos ( x )}{sin ( x )}

What is the domain of f(x)=(\sqrt[3]{4x+9})/(12x+5) ?
The domain of f(x)=(\sqrt[3]{4x+9})/(12x+5) is x<-5/12 \lor x>-5/12