What is the inverse of f(x)=7-8x^2 ?

The inverse of f(x)=7-8x^2 is sqrt(-(x-7)/8),-sqrt(-(x-7)/8)

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inverse of f(x)=7-8x^2

inverse

f (x) = 7 - 8 x^{2}

- \frac{x - 7}{8}, - - \frac{x - 7}{8}

Solution steps

y = 7 - 8 x^{2}

Replace

x

with

y

x = 7 - 8 y^{2}

Solve for

y, x = 7 - 8 y^{2}

- \frac{x - 7}{8}, - - \frac{x - 7}{8}

(x - 5)^{2} - 4

f (x) = x + 5 - 3

f (x) = x^{4} - \frac{4}{3} x^{3}

f (x) = - 4 (x - 0.44)

(3, 2), (2, 8)

What is the inverse of f(x)=7-8x^2 ?
The inverse of f(x)=7-8x^2 is sqrt(-(x-7)/8),-sqrt(-(x-7)/8)