What is the inflection x^4-32x^2+1 ?

The inflection x^4-32x^2+1 is (-4/(sqrt(3)),-1271/9),(4/(sqrt(3)),-1271/9)

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inflection x^4-32x^2+1

inflection points

x^{4} - 32 x^{2} + 1

(- \frac{4}{3}, - \frac{1271}{9}), (\frac{4}{3}, - \frac{1271}{9})

Solution steps

f^{''} (x) = 12 x^{2} - 64

Find intervals:

Concave Upward

: - \infty < x < - \frac{4}{3},

Concave Downward

: - \frac{4}{3} < x < \frac{4}{3},

Concave Upward

: \frac{4}{3} < x < \infty

Plug

x = - \frac{4}{3}

into

x^{4} - 32 x^{2} + 1 : - \frac{1271}{9}

(- \frac{4}{3}, - \frac{1271}{9})

Plug

x = \frac{4}{3}

into

x^{4} - 32 x^{2} + 1 : - \frac{1271}{9}

(\frac{4}{3}, - \frac{1271}{9})

(- \frac{4}{3}, - \frac{1271}{9}), (\frac{4}{3}, - \frac{1271}{9})

3 x - 4 y = 12

\frac{2 y + 9 x}{2} = x + 1

lo g_{5} (\frac{1 - x}{1 + x})

f (x) = \frac{x}{x + 7}

(- 1, 4), (5, - 1)

What is the inflection x^4-32x^2+1 ?
The inflection x^4-32x^2+1 is (-4/(sqrt(3)),-1271/9),(4/(sqrt(3)),-1271/9)