What is the inverse of f(x)=(x^2-9)/(5x^2) ?

The inverse of f(x)=(x^2-9)/(5x^2) is sqrt(-9/(5x-1)),-sqrt(-9/(5x-1))

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inverse of f(x)=(x^2-9)/(5x^2)

inverse

f (x) = \frac{x ^{2} - 9}{5 x ^{2}}

- \frac{9}{5 x - 1}, - - \frac{9}{5 x - 1}

Solution steps

y = \frac{x ^{2} - 9}{5 x ^{2}}

Replace

x

with

y

x = \frac{y ^{2} - 9}{5 y ^{2}}

Solve for

y, x = \frac{y ^{2} - 9}{5 y ^{2}}

- \frac{9}{5 x - 1}, - - \frac{9}{5 x - 1}

y + 2 = - 2 (x - 2)

y - 6 = 0 x - 6

f (x) = \frac{8}{x + 2}

x + 4 - \frac{1 - x}{x}

f (x) = \frac{x + 4}{- 2 x - 6}

What is the inverse of f(x)=(x^2-9)/(5x^2) ?
The inverse of f(x)=(x^2-9)/(5x^2) is sqrt(-9/(5x-1)),-sqrt(-9/(5x-1))