What is the range of f(x)=arctan(x) ?

The range of f(x)=arctan(x) is -pi/2 <f(x)< pi/2

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range of f(x)=arctan(x)

range

f (x) = arctan (x)

- \frac{π}{2} < f (x) < \frac{π}{2}

Interval Notation

(- \frac{π}{2}, \frac{π}{2})

Solution steps

The range of the basic

arctan

function is

- \frac{π}{2} < arctan (x) < \frac{π}{2}

- \frac{π}{2} < arctan (x) < \frac{π}{2}

Therefore the range is

- \frac{π}{2} < f (x) < \frac{π}{2}

f (x) = \frac{1}{x ^{2} - 2 x - x}

y = 2^{- x} + 1

lo g_{2} (2 - \frac{x}{3})

7 - x^{2}

f (x) = \frac{1}{9 - x ^{2}}

What is the range of f(x)=arctan(x) ?
The range of f(x)=arctan(x) is -pi/2 <f(x)< pi/2