What is the domain of f(x)=sqrt(x-1)+x ?

The domain of f(x)=sqrt(x-1)+x is x>= 1

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domain of f(x)=sqrt(x-1)+x

domain

f (x) = x - 1 + x

x \geq 1

Interval Notation

[1, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 1

The function domain

x \geq 1

f (x) = 7 sin (\frac{π}{6} (x - 4)) + 56

y = \frac{27 - 3 x ^{2}}{x ^{2} - 1}

(- 1, 4), (8, 2)

f (x) = \frac{x + 17}{x - 15}

f (x) = \frac{7}{( x - 4 ) ^{2}}

What is the domain of f(x)=sqrt(x-1)+x ?
The domain of f(x)=sqrt(x-1)+x is x>= 1