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midpoint
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symmetry-4x^2+6x+1symmetry domain of f(x)=\sqrt[3]{x}-3domain range of f(x)=sqrt(x/(1-\frac{1){x^2)}}range domain of 1/(x-1)domain domain of f(x)=sqrt(10-x)domain
Frequently Asked Questions (FAQ)
What is the midpoint (5,-5),(-3,-3) ?
The midpoint (5,-5),(-3,-3) is (1,-4)