What is the range of f(x)= 1/(x-2) ?

The range of f(x)= 1/(x-2) is f(x) 0

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range of f(x)= 1/(x-2)

range

f (x) = \frac{1}{x - 2}

f (x) < 0 or f (x) > 0

Interval Notation

(- \infty, 0) \cup (0, \infty)

Solution steps

The function range is the combined domain of the inverse functions

Find the inverse function(s) of:

\frac{1}{x - 2}

Inverse of

\frac{1}{x - 2} : \frac{1}{x} + 2

\frac{1}{x} + 2

Find the domain of each inverse function

Domain of

\frac{1}{x} + 2 : x < 0 or x > 0

Combine the intervals

f (x) < 0 or f (x) > 0

- x + 11

x^{2} + 6 x + 8

f (x) = 2 x^{2} - 13 x - 24

f (x) = (x - 5)^{3} + 15

f (x) = 12 + 0.75 x

What is the range of f(x)= 1/(x-2) ?
The range of f(x)= 1/(x-2) is f(x)<0\lor f(x)>0