What is the critical f(x)=(x^2+x+2)/(x-1) ?

The critical f(x)=(x^2+x+2)/(x-1) is x=-1,x=3

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critical f(x)=(x^2+x+2)/(x-1)

critical points

f (x) = \frac{x ^{2} + x + 2}{x - 1}

x = - 1, x = 3

Solution steps

\frac{x ^{2} + x + 2}{x - 1}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 1, x = 3, x = 1

Identify critical points not in

f (x)

domain

Domain of

\frac{x ^{2} + x + 2}{x - 1} : x < 1 or x > 1

\frac{x ^{2} + x + 2}{x - 1}

is not defined at

x = 1

, therefore:

x = - 1, x = 3

f (x) = x^{2} + 2 x

f (x) = \frac{9 e ^{x}}{e ^{x} - 2}

f (x) = - 2 cos (4 π x)

f (x) = \frac{19}{1 + 7 ^{- x}}

f (x) = (x - 7)^{2}

What is the critical f(x)=(x^2+x+2)/(x-1) ?
The critical f(x)=(x^2+x+2)/(x-1) is x=-1,x=3