What is the inverse of f(x)=((2x+3))/((x-1)) ?

The inverse of f(x)=((2x+3))/((x-1)) is (3+x)/(x-2)

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inverse of f(x)=((2x+3))/((x-1))

inverse

f (x) = \frac{( 2 x + 3 )}{( x - 1 )}

\frac{3 + x}{x - 2}

Solution steps

y = \frac{2 x + 3}{x - 1}

Replace

x

with

y

x = \frac{2 y + 3}{y - 1}

Solve for

y, x = \frac{2 y + 3}{y - 1}

\frac{3 + x}{x - 2}

f (x) = cos (x + π) - 1

f (x) = \frac{2}{3} x^{3} - 4 x

\frac{\frac{x}{x + 9}}{\frac{x}{x + 9} + 9}

f (x) = (\frac{5}{4})^{- x}

f (x) = 8 - x

What is the inverse of f(x)=((2x+3))/((x-1)) ?
The inverse of f(x)=((2x+3))/((x-1)) is (3+x)/(x-2)