What is the inverse of f(x)=((x-8))/((x+8)) ?

The inverse of f(x)=((x-8))/((x+8)) is (-8-8x)/(x-1)

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inverse of f(x)=((x-8))/((x+8))

inverse

f (x) = \frac{( x - 8 )}{( x + 8 )}

\frac{- 8 - 8 x}{x - 1}

Solution steps

y = \frac{x - 8}{x + 8}

Replace

x

with

y

x = \frac{y - 8}{y + 8}

Solve for

y, x = \frac{y - 8}{y + 8}

\frac{- 8 - 8 x}{x - 1}

cos (2 x + 5)

\frac{x ^{2} + 5 x + 4}{x ^{2} + 3 x + 2}

f (x) = \frac{2 x - 1}{x - 7}

f (x) = 2 x^{3} - 3 x^{2} + 5 x - 6

f (x) = \frac{8 - 5 x}{4}

What is the inverse of f(x)=((x-8))/((x+8)) ?
The inverse of f(x)=((x-8))/((x+8)) is (-8-8x)/(x-1)